document.write( "Question 745672: Ten cc of a solution of acid and water is 30% acid. I wish to dilute the acid in the mixture by adding water to make a mixture that is only 6% acid. How much pure water must I add to accomplish this? \n" ); document.write( "
Algebra.Com's Answer #453961 by josgarithmetic(39633)\"\" \"About 
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So you have 10 cc of 30% acid, and you want to add water to get 6% acid.\r
\n" ); document.write( "\n" ); document.write( "Let v = the volume of water to add.\r
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\n" ); document.write( "\n" ); document.write( "\"%2810%2A30%2Bv%2A0%29%2F%2810%2Bv%29=6\"
\n" ); document.write( "Notice that the v of water gives no acid so the factor with v is zero.
\n" ); document.write( "Same as saying \"%2810%2A30%29%2F%2810%2Bv%29=6\". Just solve for v.
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