document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=745278>Question 745278</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Cindy has 40 coins, consisting of dimes and quarters, that total $6.85. How many coins of each kind does she have?\r<BR>\n" );
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document.write( "How do I set up this problem to solve it?\r<BR>\n" );
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document.write( "thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453910 by </B><A HREF=/tutors/aboutme.mpl?userid=savvyhush23><B>savvyhush23(50)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=savvyhush23><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=savvyhush23><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1 Dime = $0.10  and 1 Quarter = $0.25\r<BR>\n" );
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document.write( "Let x - the number of dime <BR>\n" );
document.write( "y - the number of quarter\r<BR>\n" );
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document.write( "Number of coins she has: x + y = 40 coins\r<BR>\n" );
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document.write( "Now, 0.10x for dime plus 0.25y for quarter is equal to $6.85 that is,<BR>\n" );
document.write( "0.10x+0.25y=6.85\r<BR>\n" );
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document.write( "Then,<BR>\n" );
document.write( "Multiply -0.10 to (x + y = 40)  it becomes -0.10x -0.10y = -4, then add this to <BR>\n" );
document.write( "0.10x+0.25y=6.85 it yields y = 19 quarters and x = 21 dimes\r<BR>\n" );
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