document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=745571>Question 745571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 5 inches more than double its width. If the perimeter is 70 inches, find the dimensions of the rectangle by using a system of equations.\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453909 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length of a rectangle is 5 inches more than double its width means:\r<BR>\n" );
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document.write( "l=2w+5\r<BR>\n" );
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document.write( " the perimeter is 70 inches means:\r<BR>\n" );
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document.write( "2l+2w=70\r<BR>\n" );
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document.write( "or l+w=35\r<BR>\n" );
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document.write( "subbing in for l and simplifying...\r<BR>\n" );
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document.write( "(2w+5)+w=35\r<BR>\n" );
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document.write( "3w=30\r<BR>\n" );
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document.write( "so w=10\r<BR>\n" );
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document.write( "then that means \r<BR>\n" );
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document.write( "l+10=35\r<BR>\n" );
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document.write( "and so l=25\r<BR>\n" );
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document.write( "the dimensions must be: 25 inches x 10 inches </SPAN>\n" );
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