document.write( "Question 745577: Solve by back substitution.
\n" ); document.write( "x = -2
\n" ); document.write( "x + y + z = -1
\n" ); document.write( "2x + 2z = 0\r
\n" ); document.write( "\n" ); document.write( "Thank you
\n" ); document.write( "

Algebra.Com's Answer #453906 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
1---> x = -2
\n" ); document.write( "2---> x + y + z = -1
\n" ); document.write( "3---> 2x + 2z = 0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3---> 2(-2)+2z=0\r
\n" ); document.write( "\n" ); document.write( "2z=4
\n" ); document.write( "z=2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2---> (-2)+y+(2)=-1\r
\n" ); document.write( "\n" ); document.write( "y=-1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "solution: (-2,-1,2)
\n" ); document.write( "
\n" );