document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=745479>Question 745479</A>: <I><SPAN STYLE=\"word-break: break-all;\"> colud you please answer the question attached in the link below (question 12)<BR>\n" );
document.write( "www.slideshare.net/aubynjm/csec-math-january-2010&#8206; </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453876 by </B><A HREF=/tutors/aboutme.mpl?userid=savvyhush23><B>savvyhush23(50)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=savvyhush23><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=savvyhush23><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453876\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (i)the measure of inscribed angle GFH is  is always half the measure of the central angle GCH.  so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=GFH=88%2F2=44 ALIGN=MIDDLE  ALT=\"GFH=88%2F2=44\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "(ii) the polygon formed in the larger circle is a cyclic quadrilateral in which the sum of the opposite angle is 180. Thus, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180=angle+GDE%2B126 ALIGN=MIDDLE  ALT=\"180=angle+GDE%2B126\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=GDE=54 ALIGN=MIDDLE  ALT=\"GDE=54\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "(iii) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=angle+DEF+=+angle+GHF+=+180-GHE=180-126=54 ALIGN=MIDDLE  ALT=\"angle+DEF+=+angle+GHF+=+180-GHE=180-126=54\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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