document.write( "Question 745364: Hi, i've been working on this some for days and cant seem to solve it, I would ask my teacher ofcourse, but i'm homeschooled, so can someone please explain this sum to me?
\n" ); document.write( "Points A, B, C, and D lie in consecutive order on a line. If AC=4/3AB and BD=6BC, then what is AB/CD?
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Algebra.Com's Answer #453817 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "if \"AC=%284%2F3%29AB\" => \"3AC=4AB\" => \"AB=%283%2F4%29AC\"\r
\n" ); document.write( "\n" ); document.write( "and since \"BC+=AC-AB\" we can say:\r
\n" ); document.write( "\n" ); document.write( "\"BC+=%281%2F4%29AC\"\r
\n" ); document.write( "\n" ); document.write( "therefore \"AB=3BC\"
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\n" ); document.write( "furthermore, \"CD=+BD-+BC\"\r
\n" ); document.write( "\n" ); document.write( "substituting: \"CD+=+6BC+-+BC\" => \"CD+=5BC\"\r
\n" ); document.write( "\n" ); document.write( "now we have both \"AB\" and \"CD\" in terms of \"BC\", so:\r
\n" ); document.write( "\n" ); document.write( "\"AB%2FCD+=3BC%2F5BC+=3%2F5\"\r
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