document.write( "Question 64901This question is from textbook
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document.write( ": If tim leaves at 10 am traveling down a road at 16 mph. And then at 10:30 his sister leaves traveling down the same road at 36 mph. how long will it take the sister to catch up? \n" );
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Algebra.Com's Answer #45381 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If tim leaves at 10 am traveling down a road at 16 mph. And then at 10:30 his sister leaves traveling down the same road at 36 mph. how long will it take the sister to catch up? \n" ); document.write( "--------------------- \n" ); document.write( "Tim DATA: \n" ); document.write( "rate=16 mi/hr ; time=x hrs; distance= dr = 16x mi \n" ); document.write( "----------------- \n" ); document.write( "Sister DATA: \n" ); document.write( "rate=36 mi/hr ; time = x-1/2 hr ; distane = dr = 36(x-(1/2))=36x-18 mi \n" ); document.write( "------------- \n" ); document.write( "EQUATIOn: \n" ); document.write( "distance = distance \n" ); document.write( "16x=36x-18 \n" ); document.write( "20x=18 \n" ); document.write( "x=9/10 hr. or 54 minutes \n" ); document.write( "---------- \n" ); document.write( "Stan H. \n" ); document.write( " |