document.write( "Question 64901This question is from textbook
\n" ); document.write( ": If tim leaves at 10 am traveling down a road at 16 mph. And then at 10:30 his sister leaves traveling down the same road at 36 mph. how long will it take the sister to catch up? \n" ); document.write( "
Algebra.Com's Answer #45381 by stanbon(75887)\"\" \"About 
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If tim leaves at 10 am traveling down a road at 16 mph. And then at 10:30 his sister leaves traveling down the same road at 36 mph. how long will it take the sister to catch up?
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\n" ); document.write( "Tim DATA:
\n" ); document.write( "rate=16 mi/hr ; time=x hrs; distance= dr = 16x mi
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\n" ); document.write( "Sister DATA:
\n" ); document.write( "rate=36 mi/hr ; time = x-1/2 hr ; distane = dr = 36(x-(1/2))=36x-18 mi
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\n" ); document.write( "EQUATIOn:
\n" ); document.write( "distance = distance
\n" ); document.write( "16x=36x-18
\n" ); document.write( "20x=18
\n" ); document.write( "x=9/10 hr. or 54 minutes
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\n" ); document.write( "Stan H.
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