document.write( "Question 745091: I need help with:\r
\n" ); document.write( "\n" ); document.write( "1) log (x² - 1) = log 3
\n" ); document.write( "2) log base 2 (x + 3) + log base 2 (x - 3) = log base 2 7
\n" ); document.write( "3) log base x + 1 (x² - x) = 2\r
\n" ); document.write( "\n" ); document.write( "Please, help me!
\n" ); document.write( "

Algebra.Com's Answer #453743 by savvyhush23(50)\"\" \"About 
You can put this solution on YOUR website!
Just wanna ask if you're asking the value of x here?
\n" ); document.write( "Anyway,
\n" ); document.write( "a) log (x² - 1) = log 3, you can eliminate the log
\n" ); document.write( "(x² - 1) = 3
\n" ); document.write( "x = 2\r
\n" ); document.write( "\n" ); document.write( "b)log base 2 (x + 3) + log base 2 (x - 3) = log base 2 7
\n" ); document.write( "log base 2[(x + 3)(x - 3)]= log base 2 7
\n" ); document.write( "(x + 3)(x - 3) = 7
\n" ); document.write( "x² - 9 = 7
\n" ); document.write( "x = 4\r
\n" ); document.write( "\n" ); document.write( "c)log base x + 1 (x² - x) = 2
\n" ); document.write( "Note:
\n" ); document.write( "log base a (Answer) = Exponent
\n" ); document.write( "\"+a%5EExponent+=+Answer\"
\n" ); document.write( "\"+%28x+%2B+1%29%5E2+=+%28x%5E2+-+x%29\"
\n" ); document.write( "\"x%5E2%2B2x%2B1=x%5E2+-+x\"
\n" ); document.write( "\"2x%2B1=-x\"
\n" ); document.write( "\"x=-1%2F3\"
\n" ); document.write( "
\n" );