document.write( "Question 744896: Two cars leave an intersection. one travels north; the other car travels west. when the car traveling north had gone 48 miles, the distance between the cars was 8 miles more than three times the distance traveled by the car heading west. find the distance between the cars at that time.
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Algebra.Com's Answer #453721 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Two cars leave an intersection. one travels north; the other car travels west.
\n" ); document.write( " when the car traveling north had gone 48 miles, the distance between the cars was 8 miles more than three times the distance traveled by the car heading west.
\n" ); document.write( " find the distance between the cars at that time.
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\n" ); document.write( "This is a pythag problem, the distance between the cars is the hypotenuse
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\n" ); document.write( "let w = the distance traveled by the westbound car
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\n" ); document.write( "\"the distance between the cars was 8 miles more than three times the distance traveled by the car heading west.\" therefore
\n" ); document.write( "3w + 8 = the distance between the cars
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\n" ); document.write( "48^2 + w^2 = (3w+8)^2
\n" ); document.write( "FOIL (3w+8)(3w+8)
\n" ); document.write( "2304 + w^2 = 9w^2 + 48w + 64
\n" ); document.write( "2304 = 9w^2 - w^2 + 24w + 64
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "8w^2 + 48w + 64 - 2304 = 0
\n" ); document.write( "8w^2 + 48w - 2240 = 0
\n" ); document.write( "Simplify, divide by 8:
\n" ); document.write( "w^2 + 6w - 280 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(w+20)(w-14) = 0
\n" ); document.write( "the positive solution is all we want here
\n" ); document.write( "w = 14 mi traveled by the west bound car
\n" ); document.write( "then
\n" ); document.write( "3(14) + 8 = 50 mi between the cars
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\n" ); document.write( "See if that checks out on a calc
\n" ); document.write( "enter \"sqrt%2848%5E2%2B14%5E2%29\" results is 50, confirms our solution
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