document.write( "Question 745072: the sum of the digits of a three digit number is 14. The hundreds digit being 4 times the units digit. If 594 is subtracted from the number, the order of hundreds tens digits will be reversed. Find the number. \n" ); document.write( "
Algebra.Com's Answer #453694 by mananth(16946)![]() ![]() You can put this solution on YOUR website! the sum of the digits of a three digit number is 14. The hundreds digit being 4 times the units digit. If 594 is subtracted from the number, the order of hundreds tens digits will be reversed. Find the number.\r \n" ); document.write( "\n" ); document.write( "let the number be xyz\r \n" ); document.write( "\n" ); document.write( "x+y+z=14\r \n" ); document.write( "\n" ); document.write( "x=4z\r \n" ); document.write( "\n" ); document.write( "Therefore 4z+y+z=14 \n" ); document.write( "y+5z=14..........................(1)\r \n" ); document.write( "\n" ); document.write( "594 subtracted from the number\r \n" ); document.write( "\n" ); document.write( "100x+10y+z-594 = 100z+10y+x\r \n" ); document.write( "\n" ); document.write( "99x-99z=594\r \n" ); document.write( "\n" ); document.write( "/99 \n" ); document.write( "x-z=6\r \n" ); document.write( "\n" ); document.write( "But x=4z \n" ); document.write( "4z-z=6 \n" ); document.write( "3z=6 \n" ); document.write( "z=2 \n" ); document.write( "if z=2 then x= 4z=>4*2=8\r \n" ); document.write( "\n" ); document.write( "x+y+z=14 \n" ); document.write( "8+y+2=14 \n" ); document.write( "10+y=14 \n" ); document.write( "y=14-10 \n" ); document.write( "y=4\r \n" ); document.write( "\n" ); document.write( "The number is xyz \n" ); document.write( "842 \n" ); document.write( " |