document.write( "Question 64898: Any help on this would be great, I can't seem to figure it out.\r
\n" ); document.write( "\n" ); document.write( "A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108in2. What are the dimensions of the photo?
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Algebra.Com's Answer #45366 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
(X+4)(X+7)=108
\n" ); document.write( "(X+4)IS THE WIDTH (X)+ TWO 2 INCH BORDERS
\n" ); document.write( "(X+7)IS THE LENGTH (X+3)+ TWO 2 INCH BORBERS
\n" ); document.write( "(X+4)(X+7)=108
\n" ); document.write( "X^2+11X+28=108
\n" ); document.write( "X^2+11X-80=0
\n" ); document.write( "(X+16)(X-5)=0
\n" ); document.write( "X+16=0
\n" ); document.write( "X=-16 (NON SOLUTION)
\n" ); document.write( "X-5=0
\n" ); document.write( "X=5 SOLUTION. INCHES FOR THE WIDTH OF THE PICTURE
\n" ); document.write( "X+3=8 INCHES FOR THE LENGTH OF THE PICTURE.\r
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