document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=744996>Question 744996</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1cm. more than twice its height. If the area of the rectangle is 351 sq cm, what is the perimeter of the rectangle?\r<BR>\n" );
document.write( "\n" );
document.write( "I already tried to solve using these<BR>\n" );
document.write( "L=2h+1 <BR>\n" );
document.write( "              I got H=-1/3<BR>\n" );
document.write( "P=2l+2h\r<BR>\n" );
document.write( "\n" );
document.write( "I don't know what to do from there...? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453655 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453655\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = height<BR>\n" );
document.write( "2x + 1 = length   {length is 1 more than twice its height}\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Area of a rectangle is length x height\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x(2x + 1) = 351   {multiplied length x height and set equal to area, 351}<BR>\n" );
document.write( "2x² + x = 351<BR>\n" );
document.write( "2x² + x - 351 = 0<BR>\n" );
document.write( "2x² - 26x + 27x - 351 = 0   {split x into -26x and 27x}<BR>\n" );
document.write( "2x(x - 13) + 27(x - 13) = 0   {factored 2x out of 1st two terms and 27 out of last two terms - factoring by grouping}<BR>\n" );
document.write( "(2x + 27)(x - 13) = 0  {factored (x - 13) out of the two terms}<BR>\n" );
document.write( "2x + 27 = 0 or x - 13 = 0 {set each factor equal to 0}<BR>\n" );
document.write( "2x = -27 or x = 13  {subtracted 27 in 1st and added 13 in 2nd}<BR>\n" );
document.write( "x = -13.5 or x = 13  {solved each equation for x}<BR>\n" );
document.write( "x = 13 {height of a rectangle cannot be negative}<BR>\n" );
document.write( "2x + 1 = 27   {substituted 13, in for x, into 2x + 1}\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "height is 13 cm and length is 27 cm\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Perimeter of a rectangle is 2(height) + 2(length)<BR>\n" );
document.write( "P = 2(13) + 2(27)   {substituted 13 for height and 27 for length, into perimeter formula}<BR>\n" );
document.write( "= 26 + 54   {multiplied}<BR>\n" );
document.write( "= 80 {added}\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Perimeter of rectangle is 81 cm<BR>\n" );
document.write( "<br>For more help from me, visit: <a  rel=nofollow HREF= \"http://www.algebrahouse.com/\" target = \"_blank\">www.algebrahouse.com</a><br><br> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );