document.write( "Question 744989: 1) At 6 a.m., a passenger train and a freight train leave stations that
\n" ); document.write( "are 360 miles apart and travel toward each other. The passenger train averages twice the speed of the freight train. At 10 a.m., the trains pass each other.\r
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\n" ); document.write( "\n" ); document.write( "Write and solve an equation to find the average speed of each train
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Algebra.Com's Answer #453638 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Think of one train as standing still and the
\n" ); document.write( "other approaching at the sum of their speeds
\n" ); document.write( "( it doesn't matter which train is moving )
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\n" ); document.write( "Let \"+s+\" = the speed of the slower train
\n" ); document.write( "\"+2s+\" = the speed of the faster train
\n" ); document.write( "The time the moving train is traveling is
\n" ); document.write( "10 AM minus 6 AM = \"+4+\" hrs
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\n" ); document.write( "\"+360+=+%28+s+%2B+2s+%29%2A4+\"
\n" ); document.write( "\"+360+=+12s+\"
\n" ); document.write( "\"+s+=+30+\"
\n" ); document.write( "\"+2s+=+60+\"
\n" ); document.write( "The average speed of the freight train is 30 mi/hr
\n" ); document.write( "The average speed of the passenger train is 60 mi/hr
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\n" ); document.write( "check:
\n" ); document.write( "freight train:
\n" ); document.write( "\"+d%5B1%5D+=+30%2A4+\"
\n" ); document.write( "\"+d%5B1%5D+=+120+\"
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\n" ); document.write( "passenger train:
\n" ); document.write( "\"+d%5B2%5D+=+60%2A4+\"
\n" ); document.write( "\"+d%5B2%5D+=+240+\"
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\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+120+%2B+240+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+360+\" mi
\n" ); document.write( "OK\r
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