document.write( "Question 744989: 1) At 6 a.m., a passenger train and a freight train leave stations that
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document.write( "are 360 miles apart and travel toward each other. The passenger train averages twice the speed of the freight train. At 10 a.m., the trains pass each other.\r
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document.write( "Write and solve an equation to find the average speed of each train \n" );
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Algebra.Com's Answer #453638 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Think of one train as standing still and the \n" ); document.write( "other approaching at the sum of their speeds \n" ); document.write( "( it doesn't matter which train is moving ) \n" ); document.write( "-------------------------------------- \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( "The time the moving train is traveling is \n" ); document.write( "10 AM minus 6 AM = \n" ); document.write( "---------------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The average speed of the freight train is 30 mi/hr \n" ); document.write( "The average speed of the passenger train is 60 mi/hr \n" ); document.write( "--------------- \n" ); document.write( "check: \n" ); document.write( "freight train: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "--------------- \n" ); document.write( "passenger train: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |