document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=744909>Question 744909</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 	Solve the following system of linear equations using either the substitution method or the addition method:<BR>\n" );
document.write( "	1. 2x+y=5<BR>\n" );
document.write( "	2. 4x+3y=14<BR>\n" );
document.write( "Please help and show me the steps so I can learn. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453629 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453629\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem states\r<BR>\n" );
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document.write( "Solve the following system of linear equations using either the substitution method or the addition method:<BR>\n" );
document.write( "1. 2x+y=5<BR>\n" );
document.write( "2. 4x+3y=14\r<BR>\n" );
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document.write( "using equation 1, we have y= 5-2x\r<BR>\n" );
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document.write( "substitute for y in equation 2 and we get\r<BR>\n" );
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document.write( "4x + 3*(5-2x) = 14<BR>\n" );
document.write( "4x + 15-6x = 14<BR>\n" );
document.write( "-2x = -1   then<BR>\n" );
document.write( "x = 1/2 and 2*1/2 + y = 5 and y = 4\r<BR>\n" );
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document.write( " </SPAN>\n" );
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