document.write( "Question 744924: Express y as a function of x. What is the domain?
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document.write( "a) log(base 2)xy = 3log(base 2)x
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document.write( "b) log(base 5)y = 2log(base 5)x+1 + log(base 5)x-1
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document.write( "b) log(base 3)y-3 = 1 + 2log(base 3)\r
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document.write( "Can you please help me out? Thanks so much in advance:)
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document.write( "Can you also show all the steps because it would help me understand :) \n" );
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Algebra.Com's Answer #453607 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Express y as a function of x. What is the domain? \n" ); document.write( "a) log(base 2)xy = 3log(base 2)x \n" ); document.write( "--- \n" ); document.write( "log2(x)+log2(y) = log2(3^x) \n" ); document.write( "log2(y) = log2(3^x)-log2(x) \n" ); document.write( "log2(y) = log2[3^x/x] \n" ); document.write( "y = 3^x*x \n" ); document.write( "Domain: x > 0 \n" ); document.write( "============================================ \n" ); document.write( "b) log(base 5)y = 2log(base 5)x+1 + log(base 5)x-1 \n" ); document.write( "log5(y) = log5[(x+1)^2 * (x-1)] \n" ); document.write( "y = (x+1)^2*(x-1) \n" ); document.write( "Domain: x > 1 \n" ); document.write( "============================================ \n" ); document.write( "b) log(base 3)y-3 = 1 + 2log(base 3)? \n" ); document.write( "log3(y-3) = 1 + log3(?^2) \n" ); document.write( "Domain: x > 3 \n" ); document.write( "========================================== \n" ); document.write( "Note: The ? is there because your post is missing something. \n" ); document.write( "----- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |