document.write( "Question 743917: Find the vertx, the directrix, and the focus.
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document.write( "(x-4)^2 = 4(y+1) \n" );
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Algebra.Com's Answer #453600 by crazylogms(2)![]() ![]() You can put this solution on YOUR website! Given (x-4)^2 = 4(y+1) ------------------> (1)\r \n" ); document.write( "\n" ); document.write( "Comparing to (x-h)^2 = 4a(y-k) ------------------> (2)\r \n" ); document.write( "\n" ); document.write( "(h,k) = (4,-1) ----------> Vertex \r \n" ); document.write( "\n" ); document.write( "From (1) & (2),\r \n" ); document.write( "\n" ); document.write( "4a = 4 ,[ a=1 ]\r \n" ); document.write( "\n" ); document.write( "Equation of directrix y-k=-a, y+1=-1, y=-2 --------> Equation of directrix\r \n" ); document.write( "\n" ); document.write( "Vertex of Parabola (x-h=0, y-k=a) \n" ); document.write( "x=h , y=a+k \n" ); document.write( "x=4 , y=0 \n" ); document.write( "(4,0) ---------------------------------> Vertex of Parabola.\r \n" ); document.write( "\n" ); document.write( "Cheers \n" ); document.write( " |