document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=744750>Question 744750</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE HEIGHT OF A TRIANGLE IS 3 METERS GREATER THAN THE BASE. THE AREA OF A TRIANGLE IS 35 SQUARE METERS.  FIND THE LENGTH OF THE BASE AND THE HEIGHT OF THE TRIANGLE. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453583 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Represent the height as (x + 3) and the base as x.<BR>\n" );
document.write( "Area of triangle = 1/2 (base x height) = 35 m^2<BR>\n" );
document.write( "1/2 (x times (x + 3)) = x^2 + 3/2.<BR>\n" );
document.write( "x^2 + 3/2 = 35 m^2<BR>\n" );
document.write( "x^2 + 3x = 35 x 2<BR>\n" );
document.write( "x^2 + 3x = 70<BR>\n" );
document.write( "x^2 + 3x - 70 = 0<BR>\n" );
document.write( "(x + 10)(x - 7)\r<BR>\n" );
document.write( "\n" );
document.write( "The answer is x = 7<BR>\n" );
document.write( "Height = 10m and base = 7m </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );