document.write( "Question 744771: Hello! I need help on this question. I understand all the speed x time equals distance and so, but i don't quite get this kinds of questions. A man walks to work at 3 1/2 kmph and is one minute late. If he walked at 3 1/3 kmph he would have been three minutes late. What is the distance to his office? Thanks :) \n" ); document.write( "
Algebra.Com's Answer #453541 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the right time be t\r \n" ); document.write( "\n" ); document.write( "speed = 3 1/2 kmph time taken = t+(1/60) hours\r \n" ); document.write( "\n" ); document.write( "speed =3 1/3 kmph time taken = t + (3/60) hours\r \n" ); document.write( "\n" ); document.write( "in both cases distance is the same\r \n" ); document.write( "\n" ); document.write( "d=rt\r \n" ); document.write( "\n" ); document.write( "3 1/2 *( t+(1/60) )= distance\r \n" ); document.write( "\n" ); document.write( "3 1/3 (t + (3/60))= distance\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 1/2 *( t+(1/60) )= 3 1/3 (t + (3/60))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7/2((60t+1)/60) = 10/3((60t+3)/60)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cross multiply\r \n" ); document.write( "\n" ); document.write( "21(60t+1)/60 = 20(60t+3)/60\r \n" ); document.write( "\n" ); document.write( "21(60t+1)=20(60t+3)\r \n" ); document.write( "\n" ); document.write( "1260t+21=1200t+60\r \n" ); document.write( "\n" ); document.write( "60t=60-21\r \n" ); document.write( "\n" ); document.write( "60t=39 \n" ); document.write( "t= 39/60\r \n" ); document.write( "\n" ); document.write( "t= 39 minutes\r \n" ); document.write( "\n" ); document.write( "With speed of 3 1/2 he takes one minute more => 39+1=40 minutes\r \n" ); document.write( "\n" ); document.write( "d=rt \r \n" ); document.write( "\n" ); document.write( "d= (7/2) *(40/60)\r \n" ); document.write( "\n" ); document.write( "d= 7/3 =2.33 km\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |