document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=744729>Question 744729</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pharmacist has 6L of a mixture that is 20% alcohol. How much pure alcohol must be added to obtain a mixture that is 70% alcohol? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453528 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453528\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A pharmacist has 6L of a mixture that is 20% alcohol.<BR>\n" );
document.write( " How much pure alcohol must be added to obtain a mixture that is 70% alcohol?<BR>\n" );
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document.write( "let x = amt of pure alcohol required<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(6-x) = amt of 20% alcohol required<BR>\n" );
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document.write( ".20(6-x) + x = .70(6)<BR>\n" );
document.write( "1.2 - .2x + x = 4.2<BR>\n" );
document.write( ".8x = 4.2 - 1.2<BR>\n" );
document.write( ".8x = 3<BR>\n" );
document.write( "x = 3/.8<BR>\n" );
document.write( "x = 3.75 L of pure alcohol required<BR>\n" );
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document.write( "Check: .2(2.25) + 3.75 = .7(6)<BR>\n" );
document.write( ".45 + 3.75 = 4.2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );