document.write( "Question 744709: 1. Solve the following exponential equations
\n" ); document.write( "a) 3^(2x-1) = 2^(x+2)
\n" ); document.write( "b) 2^(x+1) = 5^(1-x)
\n" ); document.write( "c) 2^(x+1)/ 5^x = 3\r
\n" ); document.write( "\n" ); document.write( "Can you please help me out? Thanks so much in advance:)
\n" ); document.write( "Can you please show all the steps it would really help me understand:)\r
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Algebra.Com's Answer #453520 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
a)
\n" ); document.write( "\"3%5E%282x-1%29+=+2%5E%28x%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "Expanding exponents...\r
\n" ); document.write( "\n" ); document.write( "\"3%5E%282x%29%2A3%5E%28-1%29+=+2%5Ex%2A2%5E2\"\r
\n" ); document.write( "\n" ); document.write( "simplifying...\r
\n" ); document.write( "\n" ); document.write( "\"3%5E%282x%29%2F3+=+2%5Ex%2A4\"\r
\n" ); document.write( "\n" ); document.write( "\"%283%5E2%29%5Ex%2F3=4%2A2%5Ex\"\r
\n" ); document.write( "\n" ); document.write( "Next we isolate x...\r
\n" ); document.write( "\n" ); document.write( "\"9%5Ex%2F3=4%2A2%5Ex\"\r
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\n" ); document.write( "\n" ); document.write( "\"9%5Ex%2F2%5Ex=4%2A3\"\r
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\n" ); document.write( "\n" ); document.write( "Key step: we can combine the bases under the exponent since the exponent for both of them is the same...\r
\n" ); document.write( "\n" ); document.write( "\"%289%2F2%29%5Ex=12\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%289%2F2%29%5Ex%29=log12\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2Alog%289%2F2%29=log12%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=log12%2Flog%289%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "which can be rewritten as...\r
\n" ); document.write( "\n" ); document.write( "\"log12%2F%28log9-log2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Less steps for the remaining parts...\r
\n" ); document.write( "\n" ); document.write( "b)
\n" ); document.write( "\"+2%5E%28x%2B1%29+=+5%5E%281-x%29\"\r
\n" ); document.write( "\n" ); document.write( "\"+2%5Ex%2A2+=+5%2A5%5E%28-x%29\"\r
\n" ); document.write( "\n" ); document.write( "\"2%5Ex%2F5%5Ex=5%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2F5%29%5Ex=5%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2F5%29%5Ex=5%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2F5%29%5Ex=%282%2F5%29%5E%28-1%29\"\r
\n" ); document.write( "\n" ); document.write( "after taking log of both sides and cancelling (i.e. if the bases are equal the the exponents are also equal to each other)\r
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\n" ); document.write( "\n" ); document.write( "x=-1\r
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\n" ); document.write( "\n" ); document.write( "Now with maximum efficiency we solve the last...\r
\n" ); document.write( "\n" ); document.write( "c)
\n" ); document.write( "\"2%5E%28x%2B1%29%2F+5%5Ex+=+3\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2A2%5Ex%29%2F5%5Ex=3\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2F5%29%5Ex=3%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%282%2F5%29%5Ex%29=log%283%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%28log3-log2%29%2F%28log2-log5%29\"
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