document.write( "Question 744624: Given that sin A= -4/5 where A is in quadrant 3 and sin B= 12/13 where B is in quadrant 2. Find:\r
\n" ); document.write( "\n" ); document.write( "A. cosA\r
\n" ); document.write( "\n" ); document.write( "B. cosB\r
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\n" ); document.write( "\n" ); document.write( "D. tan(2A)\r
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Algebra.Com's Answer #453509 by lwsshak3(11628)\"\" \"About 
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Given that sin A= -4/5 where A is in quadrant 3 and sin B= 12/13 where B is in quadrant 2. Find:
\n" ); document.write( "A. cosA=\"-sqrt%281-sin%5E2%28A%29%29=-sqrt%281-%2816%2F25%29%29=-sqrt%289%2F25%29=-3%2F5\"
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\n" ); document.write( "B. cosB =\"-sqrt%281-sin%5E2%28B%29%29=-sqrt%281-%28144%2F169%29%29=-sqrt%2825%2F169%29=-5%2F13\"
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\n" ); document.write( "C. sec(A-B)=1/cos(A-B)
\n" ); document.write( "cos(A-B)=cosA cosB+SinA sinB=-3/5*-5/13+(-4/5)*12/13=15/65-48/65=-33/65
\n" ); document.write( "sec(A-B)=-65/33
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\n" ); document.write( "D. tan(2A)=(2tanA)/(1-tan^2A)
\n" ); document.write( "tanA=sinA/cosA=(-4/5)/(-3/5)=4/3
\n" ); document.write( "tan(2A)=(8/3)/(1-16/9)=(8/3)/(-7/9)=-72/21
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\n" ); document.write( "E. cos(B/2)=\"sqrt%28%281%2BcosB%29%2F2%29=sqrt%28%281%2B%28-5%2F13%29%29%2F2%29%29\"=√((8/13)/2))=√(8/26)
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