document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=744706>Question 744706</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Show that log(base 1/c)x = log(base c)1/x\r<BR>\n" );
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document.write( "Can you please help me out? Thanks so much in advance:)<BR>\n" );
document.write( "Can you please show all the steps it would really help me understand:)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453501 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453501\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. Show that log(base 1/c)x = log(base c)1/x<BR>\n" );
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document.write( "log(base 1/c)x = m --> (1/c)^m = x --> 1/(c^m) = x --> c^(-m) = x<BR>\n" );
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document.write( "log(base c)1/x = n --> c^n = 1/x --> c^(-n) = x<BR>\n" );
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document.write( "c^-n = x<BR>\n" );
document.write( "c^-m = x<BR>\n" );
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document.write( "m = n<BR>\n" );
document.write( "log(base 1/c)x = log(base c)1/x<BR>\n" );
document.write( "QED<BR>\n" );
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