document.write( "Question 744690: Twice of William's age adds on to Michael's age to make 41. William is 3 years older than Michael. We are trying to find William's age. I tried making two equations, including one that will solve for William's age. To find Michael first, I got a decimal. I am not sure what to do. I have tried. \n" ); document.write( "
Algebra.Com's Answer #453500 by ankor@dixie-net.com(22740)\"\" \"About 
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Twice of William's age adds on to Michael's age to make 41.
\n" ); document.write( "2w + m = 41
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\n" ); document.write( "William is 3 years older than Michael.
\n" ); document.write( "w = m + 3
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\n" ); document.write( "in the first equation replace w with (m+3)
\n" ); document.write( "2(m+3) + m = 41
\n" ); document.write( "2m + 6 + m = 41
\n" ); document.write( "2m + m = 41 - 6
\n" ); document.write( "3m = 35
\n" ); document.write( "m = 11\"2%2F3\"
\n" ); document.write( "Find w
\n" ); document.write( "w = 11\"2%2F3\" + 3
\n" ); document.write( "w = 14\"2%2F3\", a decimal just like you got
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\n" ); document.write( "See if that checks out in the 1st equation
\n" ); document.write( "2w + m = 41
\n" ); document.write( "2(14\"2%2F3\") + 11\"2%2F3\"
\n" ); document.write( "29\"1%2F3\" + 11\"2%2F3\" = 41\r
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