document.write( "Question 744680: How do I solve? and Which method would I use for this one substitution or elimination? I automatically think elimination because of the = sign. Showing work would be helpful, I am printing and using as a study guide. This is very frustrating :/ Thank you so much!\r
\n" ); document.write( "\n" ); document.write( "5x + 3y = 4
\n" ); document.write( "x - 4y = 3 \n" ); document.write( "
Algebra.Com's Answer #453496 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
5x + 3y = 4 ....(1)
\n" ); document.write( "x - 4y = 3 ....(2)\r
\n" ); document.write( "\n" ); document.write( "You now multiply line (1) by 4 and line (2) by 3
\n" ); document.write( "This is done to remove one of the unknowns namely 'y'\r
\n" ); document.write( "\n" ); document.write( "20x + 12y = 16
\n" ); document.write( "3x - 12y = 9\r
\n" ); document.write( "\n" ); document.write( "Add\r
\n" ); document.write( "\n" ); document.write( "23x = 25
\n" ); document.write( " x = 25/23\r
\n" ); document.write( "\n" ); document.write( "Substitute x = 25/23 into x - 4y = 3 ...(2)\r
\n" ); document.write( "\n" ); document.write( " 25/23 - 4y = 3\r
\n" ); document.write( "\n" ); document.write( " - 4y = 3 - 25/23\r
\n" ); document.write( "\n" ); document.write( "Change 3 to 23rds \r
\n" ); document.write( "\n" ); document.write( " - 4y = 69/23 -25/23\r
\n" ); document.write( "\n" ); document.write( " -4y = 44/23\r
\n" ); document.write( "\n" ); document.write( " -y = 44/92\r
\n" ); document.write( "\n" ); document.write( " y = - 44/92 = -22/46 = -11/23\r
\n" ); document.write( "\n" ); document.write( " x = 25/23 : y = -11/23
\n" ); document.write( " \n" ); document.write( "
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