document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=744623>Question 744623</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much pure acid should be mixed with gallons of a 50% acid solution in order to get a 80% acid solution  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453488 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453488\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You omitted how many gallons of the 50% acid.  Call this value g.  So you have g gallons of 50% acid.  You would add v gallons of the 100% acid.\r<BR>\n" );
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document.write( "and you want to solve for v. </SPAN>\n" );
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