document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=744621>Question 744621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In triangle ABC, angle A is 30 more than angle B. Angle C equals the sum of angle A and B. Find the measure of each of the three angles.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453466 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In triangle ABC, angle A is 30 more than angle B.<BR>\n" );
document.write( "if B=x then A=x+30<BR>\n" );
document.write( "Angle C equals the sum of angle A and B.<BR>\n" );
document.write( "so C=x+x+30<BR>\n" );
document.write( "now A+B+C=180<BR>\n" );
document.write( "so x+30+x+x+x+30=180<BR>\n" );
document.write( "or 4x+60=180<BR>\n" );
document.write( "or 4x=180-60=120<BR>\n" );
document.write( "or x=30=B<BR>\n" );
document.write( "so A=30+30=60 & C=30+60=90 </SPAN>\n" );
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