document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=744530>Question 744530</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If one of the roots of the equation 2x^2 - x + C =0 is doubled the other root, find C. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453439 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If one of the roots of the equation 2x^2 - x + C = 0 is double the other root, find C.\r<BR>\n" );
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document.write( "We know that the roots have to be different signs, factors to<BR>\n" );
document.write( "(2x+1)(x-1) FOILs to 2x^2 - 2x + x - 1 = 2x^2 - x - 1; c = -1<BR>\n" );
document.write( "Roots<BR>\n" );
document.write( "2x = -1<BR>\n" );
document.write( "x = -.5<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x = 1<BR>\n" );
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