document.write( "Question 64853: Urgent please help!!!\r
\n" ); document.write( "\n" ); document.write( "-1+41log3(-3x)=7\r
\n" ); document.write( "\n" ); document.write( "Solve please!!!! \n" ); document.write( "
Algebra.Com's Answer #45343 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
Urgent please help!!!\r\n" );
document.write( "\r\n" );
document.write( " -1 + 41log3(-3x) = 7\r\n" );
document.write( "\r\n" );
document.write( "Isolate the log term by adding 1\r\n" );
document.write( "to both sides:\r\n" );
document.write( "\r\n" );
document.write( "     41log3(-3x) = 8\r\n" );
document.write( "\r\n" );
document.write( "Divide both sides by 41\r\n" );
document.write( "\r\n" );
document.write( "       log3(-3x) = 8/41\r\n" );
document.write( "\r\n" );
document.write( "Use this rule of logarithms:\r\n" );
document.write( "\r\n" );
document.write( "The logarithm equation logBA = C can be \r\n" );
document.write( "rewritten equivalently as the exponential\r\n" );
document.write( "equation A = BC\r\n" );
document.write( "\r\n" );
document.write( "           -3x = 38/41\r\n" );
document.write( "\r\n" );
document.write( "Divide both sides by -3\r\n" );
document.write( "\r\n" );
document.write( "             x = (38/41) ÷ (-3) \r\n" );
document.write( "\r\n" );
document.write( "             x = -(38/41)÷(31)\r\n" );
document.write( "\r\n" );
document.write( "Subtract exponents of 3:\r\n" );
document.write( "\r\n" );
document.write( "             x = -38/41-1\r\n" );
document.write( "\r\n" );
document.write( "             x = -38/41-41/41\r\n" );
document.write( "\r\n" );
document.write( "             x = -3-33/41\r\n" );
document.write( "\r\n" );
document.write( "             x = -1/(333/41) \r\n" );
document.write( "  \r\n" );
document.write( "             x = -.413024273, approximately\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );