document.write( "Question 64815: In the morning, May drove to an appointment at 50 mph. Her average speed on the return trip on the afternoon was 40 mph. The return trip took 1/8 hour longer. How far did she travel to the appointment? \n" ); document.write( "
Algebra.Com's Answer #45340 by ankor@dixie-net.com(22740)\"\" \"About 
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In the morning, May drove to an appointment at 50 mph. Her average speed on the return trip on the afternoon was 40 mph. The return trip took 1/8 hour longer. How far did she travel to the appointment?
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\n" ); document.write( "An easy way is to first find the time required at 50 mph
\n" ); document.write( "Let t = time at 50 mph
\n" ); document.write( "Then (t+(1/8)) = time at 40 mph
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\n" ); document.write( "Write a distance equation: dist = speed * time:
\n" ); document.write( "Dist there = dist back
\n" ); document.write( "50t = 40(t+(1/8))
\n" ); document.write( "50t = 40t + 5
\n" ); document.write( "50t - 40t = 5
\n" ); document.write( "10t = 5
\n" ); document.write( "t = 5/10 = 1/2 hr at 50 mph
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\n" ); document.write( "Dist = 50*(1/2) = 25 miles
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\n" ); document.write( "Check using 40 mph:
\n" ); document.write( "40((1/2)+(1/8) =
\n" ); document.write( "40 * (5/8) = 25 mi back
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\n" ); document.write( "Did this make sense to you? Any questions?\r
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