document.write( "Question 744487: 1. Solve the following equations
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document.write( "a) 5^(2x) + 5^(x) - 6 = 0 (hint let y = 5^(x)\r
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document.write( "Can you please help me out? Thanks so much in advance:)
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document.write( "Can you please show all the steps it would really help me understand:) \n" );
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Algebra.Com's Answer #453344 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! a) 5^(2x) + 5^(x) - 6 = 0 (hint let y = 5^(x) \n" ); document.write( ". \n" ); document.write( "We Let y = 5^x \n" ); document.write( "if so, we can rewrite: \n" ); document.write( "5^(2x) + 5^(x) - 6 = 0 \n" ); document.write( "AS \n" ); document.write( "y^2 + y - 6 = 0 \n" ); document.write( "now, we factor : \n" ); document.write( "(y+3)(y-2) = 0 \n" ); document.write( "y = {-3, 2) \n" ); document.write( ". \n" ); document.write( "But, we still need to find x: \n" ); document.write( "since \n" ); document.write( "y = 5^x \n" ); document.write( "we substitute each value of y to find x: \n" ); document.write( "-3 = 5^x \n" ); document.write( " \n" ); document.write( "since we can't take the log of a negative value we throw out this solution. \n" ); document.write( ". \n" ); document.write( "2 = 5^x \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "0.431 = x \n" ); document.write( " \n" ); document.write( " |