document.write( "Question 744508: it takes a boat 9 hours to go a distance of 270 miles against the current and 3 hours to make the return trip with the current. Find the rate of the current \n" ); document.write( "
Algebra.Com's Answer #453339 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! it takes a boat 9 hours to go a distance of 270 miles against the current and 3 hours to make the return trip with the current. Find the rate of the current \n" ); document.write( "------- \n" ); document.write( "Against current: \n" ); document.write( "rate = 270/9 = 30 mph \n" ); document.write( "----- \n" ); document.write( "With current: \n" ); document.write( "rate = 270/3 = 90 mph \n" ); document.write( "--------------------------- \n" ); document.write( "Equations: \n" ); document.write( "b + c = 90 mph \n" ); document.write( "b - c = 30 mph \n" ); document.write( "------------------ \n" ); document.write( "2b = 120 \n" ); document.write( "b = 60 mph \n" ); document.write( "------------------ \n" ); document.write( "Solve for \"c\": \n" ); document.write( "b + c = 90 \n" ); document.write( "60 + c = 90 \n" ); document.write( "current = 30 mph \n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |