document.write( "Question 744508: it takes a boat 9 hours to go a distance of 270 miles against the current and 3 hours to make the return trip with the current. Find the rate of the current \n" ); document.write( "
Algebra.Com's Answer #453339 by stanbon(75887)\"\" \"About 
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it takes a boat 9 hours to go a distance of 270 miles against the current and 3 hours to make the return trip with the current. Find the rate of the current
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\n" ); document.write( "Against current:
\n" ); document.write( "rate = 270/9 = 30 mph
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\n" ); document.write( "With current:
\n" ); document.write( "rate = 270/3 = 90 mph
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\n" ); document.write( "Equations:
\n" ); document.write( "b + c = 90 mph
\n" ); document.write( "b - c = 30 mph
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\n" ); document.write( "2b = 120
\n" ); document.write( "b = 60 mph
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\n" ); document.write( "Solve for \"c\":
\n" ); document.write( "b + c = 90
\n" ); document.write( "60 + c = 90
\n" ); document.write( "current = 30 mph
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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