document.write( "Question 744471: how do I find the equation of a line that passes through 1,2 and is perpendicular to y equals negative three fourths X plus two and three fourths \n" ); document.write( "
Algebra.Com's Answer #453334 by mananth(16946)\"\" \"About 
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1 y = - 3/ 4 x + 11/4
\n" ); document.write( "Divide by 1
\n" ); document.write( " y = - 3/ 4 x + 11/4
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = - 3/4
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal 4/3
\n" ); document.write( "Because m1*m2 =-1
\n" ); document.write( "The slope of the required line will be4/3
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\n" ); document.write( "m=4/3 ,point ( 1 , 2 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "2 = 4/ 3 + b
\n" ); document.write( "b= 2/3
\n" ); document.write( "m= 4/3
\n" ); document.write( "The required equation is y = 4/ 3 x + 2/ 3
\n" ); document.write( "m.ananth@hotmail.ca
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