document.write( "Question 744441: Hello, this isn't an arithmetic sequence question, but a geometric one. I need to find the rate of the following geometric sequence,
\n" ); document.write( "9 (nine), 3√3 (three square root of 3),3(three),... and the next three terms of the sequence. How can I do it?
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Algebra.Com's Answer #453325 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
\"9+-3sqrt%283%29-3\"\r
\n" ); document.write( "\n" ); document.write( "r= \"3sqrt%283%29%2F9\"=>\"1%2Fsqrt%283%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r%3C1\"\r
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\n" ); document.write( "\n" ); document.write( "\"tn=+ar%5E%28n-1%29\"\r
\n" ); document.write( "\n" ); document.write( "a=9, r= sqrt(1/3)\r
\n" ); document.write( "\n" ); document.write( "\"t4=9%2A%281%2Fsqrt%283%29%29%5E%284-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t4=9%2A%281%2Fsqrt%283%29%29%5E%283%29\"\r
\n" ); document.write( "\n" ); document.write( "\"t4=+9%2A%281%2F3sqrt%283%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"t4=sqrt%283%29\"\r
\n" ); document.write( "\n" ); document.write( "you find the 5th and 6th in the same way
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