document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=744420>Question 744420</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, please help me answer this problem: What quantity of 60 percent acid solution must be mixed with a 30 percent solution to produce 630 mL of a 50 percent solution? Im not too sure where to begin maybe make a table? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453318 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem states\r<BR>\n" );
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document.write( "What quantity of 60 percent acid solution must be mixed with a 30 percent solution to produce 630 mL of a 50 percent solution?\r<BR>\n" );
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document.write( "let x = amount of .60 solution<BR>\n" );
document.write( "then 630 - x = .30 solution<BR>\n" );
document.write( "and .50*630 = 315 ml of alcohol\r<BR>\n" );
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document.write( "then\r<BR>\n" );
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document.write( ".6x + .3(630 - x) = 315<BR>\n" );
document.write( ".3x = 315 - 189 <BR>\n" );
document.write( ".3x = 126   and\r<BR>\n" );
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document.write( "x = 420\r<BR>\n" );
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document.write( "420ml of 60% solution and <BR>\n" );
document.write( "210ml pf 30% solution\r<BR>\n" );
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document.write( " </SPAN>\n" );
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