document.write( "Question 743933: Identify the vertex, focus, and directrix of the graph of y=1/12(x+5)^2-3 \n" ); document.write( "

Algebra.Com's Answer #453312 by lwsshak3(11628) $\"\"$ $\"About$

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Identify the vertex, focus, and directrix of the graph of
\n" ); document.write( "y=1/12(x+5)^2-3
\n" ); document.write( "rewrite equation to basic form: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex
\n" ); document.write( "1/12(x+5)^2=y+3
\n" ); document.write( "(x+5)^2=12(y+3)
\n" ); document.write( "vertex:(-5,-3)
\n" ); document.write( "axis of symmetry: x=-5
\n" ); document.write( "4p=12
\n" ); document.write( "p=3
\n" ); document.write( "focus: (-5,0)
\n" ); document.write( "directrix:(-5,-6) \r
\n" ); document.write( "\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-10%2C10%2C+-10%2C+10%2C%281%2F12%29%28x%2B5%29%5E2-3%29+\"$ \n" ); document.write( "

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