document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=744340>Question 744340</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a fraction becomes 5/6 if 3 is added to both the numerator and denominator.if however 3 is subtracted from both numerator and denominator the fraction becomes 2/3 find the fraction </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453286 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453286\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (X+3)/(Y+3)=5/6<BR>\n" );
document.write( "6(X+3)=5(Y+3)<BR>\n" );
document.write( "6X+18=5Y+15<BR>\n" );
document.write( "6X-5Y=15-16<BR>\n" );
document.write( "6X-5Y=-1<BR>\n" );
document.write( "(X-3)/(Y-3)=2/3<BR>\n" );
document.write( "3(X-3)=2(Y-3)<BR>\n" );
document.write( "3X-9=2Y-6<BR>\n" );
document.write( "3X-2Y=-6+9<BR>\n" );
document.write( "#######################<BR>\n" );
document.write( "3X-2Y=3 MULTIPLY BY -2 & ADD.<BR>\n" );
document.write( "6X-5Y=-1<BR>\n" );
document.write( "-6X+4Y=-6<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "-Y=-7<BR>\n" );
document.write( "Y=7 ANS.<BR>\n" );
document.write( "6X-5*7=-1<BR>\n" );
document.write( "6X-35=-1<BR>\n" );
document.write( "6X=35-1<BR>\n" );
document.write( "6X=34<BR>\n" );
document.write( "X=34/6<BR>\n" );
document.write( "X=5 2/3 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "3(5 2/3)-2*7=3<BR>\n" );
document.write( "3(17/3)-14=3<BR>\n" );
document.write( "17-14=3<BR>\n" );
document.write( "3=3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );