document.write( "Question 64828: I can not figure out this math problem and need help. The question says, \"Bill wnats 30 pounds of a coffee blend that he can sell for $7.00 per pound. If he has coffee that sells for $6.00 a pound and another brand that sells for $7.50 per pound, how many pounds of each brand should he use to make his blend?\" \n" ); document.write( "
Algebra.Com's Answer #45326 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=number of pounds of the $6.00 brand
\n" ); document.write( "Then 30-x=number of pounds of $7.50 brand\r
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\n" ); document.write( "\n" ); document.write( "Now we know that the amount of money generated by the $6.00 brand ($6.00)(x) plus the amount of money generated by the $7.50 brand (30-x)($7.50) must equal the amount of money generated by the final blend (30)($7.00) so our equation to solve is:\r
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\n" ); document.write( "\n" ); document.write( "6.00(x)+7.50(30-x)=(30)(7.00) simplifying we have:\r
\n" ); document.write( "\n" ); document.write( "6x-7.5x+225=210 collecting like terms we get:
\n" ); document.write( "-1.5x=-225+210=-15
\n" ); document.write( "x=10 lb for the $6.00 brand
\n" ); document.write( "30-x=30-10=20 lb for the $7.50 brand\r
\n" ); document.write( "\n" ); document.write( "ck
\n" ); document.write( "6.00(10)+7.50(30-10)=30(7.00)
\n" ); document.write( "60+150=210
\n" ); document.write( "210=210\r
\n" ); document.write( "\n" ); document.write( "Hope this helps. Happy holidays.--------ptaylor
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