document.write( "Question 744284: the denominator of a fraction exceeds the numerator by 5 and if 3 be added to both the fraction becomes 3/4 .the fraction is \n" ); document.write( "
Algebra.Com's Answer #453240 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "let the numerator of a fraction be \"a\" and the denominator \"b\"\r
\n" ); document.write( "\n" ); document.write( "fraction is \"a%2Fb\"\r
\n" ); document.write( "\n" ); document.write( "if the denominator of a fraction \"b\" exceeds the numerator \"a\" by \"5\", we have\r
\n" ); document.write( "\n" ); document.write( "\"b=a%2B5\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "then, our fraction looks like this:\r
\n" ); document.write( "\n" ); document.write( "\"a%2F%28a%2B5%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " and if \"3\" be added to \"both\" the fraction becomes \"3%2F4\"; so, we have\r
\n" ); document.write( "\n" ); document.write( "\"%28a%2B3%29%2F%28a%2B5%2B3%29=3%2F4\"......now solve for \"a\"\r
\n" ); document.write( "\n" ); document.write( "\"%28a%2B3%29%2F%28a%2B8%29=3%2F4\"....cross multiply\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28a%2B3%29%2A4=3%28a%2B8%29\"\r
\n" ); document.write( "\n" ); document.write( "\"4a%2B12=3a%2B24\"\r
\n" ); document.write( "\n" ); document.write( "\"4a-3a=24-12\"\r
\n" ); document.write( "\n" ); document.write( "\"a=12\"\r
\n" ); document.write( "\n" ); document.write( "find \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"b=a%2B5\"\r
\n" ); document.write( "\n" ); document.write( "\"b=12%2B5\"\r
\n" ); document.write( "\n" ); document.write( "\"b=17\"\r
\n" ); document.write( "\n" ); document.write( "so, your fraction is: \"a%2Fb=12%2F17\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );