document.write( "Question 744222: David Saxon invested $25000 in two different corporate bonds for 1 year.One bond pays a 4.5% simple interest rate. and the other pays 6% simple interest rate. The Total annual interest David received from both bonds was $1380. Find the amount he invested for each bond. For 1 year,the simple interest on a specific corporate bond is found by multiplying the amount invested by the simple interest rate. \n" ); document.write( "
Algebra.Com's Answer #453226 by mananth(16946)\"\" \"About 
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Part I 4.50% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 6.00% per annum ------------ Amount invested = y
\n" ); document.write( " 25000
\n" ); document.write( "Interest----- 1380.00
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\n" ); document.write( "Part I 4.50% per annum ---x
\n" ); document.write( "Part II 6.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 25000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "4.50% x + 6.00% y= 1380
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4.5 x + 6 y= 138000.00 --------2
\n" ); document.write( "Multiply (1) by -4.5
\n" ); document.write( "we get
\n" ); document.write( "-4.5 x -4.5 y= -112500.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 1.5 y= 25500
\n" ); document.write( "divide by 1.5
\n" ); document.write( " y = 17000
\n" ); document.write( "Part I 4.50% $ 8000
\n" ); document.write( "Part II 6.00% $ 17000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "8000 --------- 4.50% ------- 360.00
\n" ); document.write( "17000 ------------- 6.00% ------- 1020.00
\n" ); document.write( "Total -------------------- 1380.00
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\n" ); document.write( "m.ananth@hotmail.ca
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