document.write( "Question 64809: a silversmith has two alloys. the first alloy is 18% silver and the second is 54% silver. how many grams of each should be mixed to produce 120 grams of an alloy that is 39% silver?
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Algebra.Com's Answer #45321 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=amount of 18% silver
\n" ); document.write( "Then 120-x=amount of 54% silver\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure silver in the 18% mixture (.18)(x) plus the amount of pure silver in the 54% mixture (120-x)(.54) must equal the amount of pure silver in the final mixture (120)(.39) so our equation to solve is:\r
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\n" ); document.write( "\n" ); document.write( ".18x+.54(120-x)=(120)(.39) simplifying we get:\r
\n" ); document.write( "\n" ); document.write( ".18x-.54x+64.8=46.8 collecting like terms we have:\r
\n" ); document.write( "\n" ); document.write( "-.36x=-64.8+46.8=-18
\n" ); document.write( "x=50 grams of 18% silver\r
\n" ); document.write( "\n" ); document.write( "and 120-x=120-50 =70 grams of 54% silver\r
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\n" ); document.write( "70(.54)+50(.18)=120(.39)
\n" ); document.write( "37.8+9=46.8
\n" ); document.write( "46.8=46.8\r
\n" ); document.write( "\n" ); document.write( "Hope this helps. Happy holidays.----ptaylor
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