document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=743951>Question 743951</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if i make a 67 one six weeks and a 54 on the other what do i have to make in the third six weeks to avarage out at 70? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #453104 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=453104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "A bit confusing about the \"3rd six weeks\" but I think I get your drift. Try this:<BR>\n" );
document.write( "(67+54+x)/3=70<BR>\n" );
document.write( "Multiply by 3 and add to get:<BR>\n" );
document.write( "121+x=210<BR>\n" );
document.write( "Subtract 121:<BR>\n" );
document.write( "x=89 dollars<BR>\n" );
document.write( "RJ<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );