document.write( "Question 743804: Monique wants to create a dog fence that has a perimeter of 112 feet. She knows that she wants the length to be 16 feet longer than the width. \r
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document.write( "Describe a method to calculate the length and the width of the fence.
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Algebra.Com's Answer #453063 by davethejackal(28) You can put this solution on YOUR website! Assuming the fence is rectangular in shape, then the total length of the perimeter is the length of all the sides = twice its length + twice its width \n" ); document.write( "=2l + 2w\r \n" ); document.write( "\n" ); document.write( "Where w = width of the fence, l = length (both measured in feet)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"a perimeter of 112 feet\" so \n" ); document.write( "2l + 2w = 112 | [1]\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "but \"she wants the length to be 16 feet longer than the width\" so \n" ); document.write( "l = w +16 | [2]\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence [1] becomes 2l + 2w = 2(w+16) + 2w = 4w + 32 = 112 \n" ); document.write( "Thus 4w = 112-32 \n" ); document.write( "And w = (112-32) / 4 = 80/4 = 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "[2] gives us l = w +16 = 20+16 = 36\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking that the total length is 112 using [1] \n" ); document.write( "2l+2w = 2(36)+2(20) = 72 + 40 = 112 QED\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence the length of the fence is 32 ft and the width 20 ft. \n" ); document.write( " |