document.write( "Question 743731: Find the equation of the hyperbola that the transverse axis is parallel to the x-axis, center at (2,-2), passing through (2+3√2,0) and (2+3√10,4). \n" ); document.write( "
Algebra.Com's Answer #453037 by lwsshak3(11628)\"\" \"About 
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Find the equation of the hyperbola that the transverse axis is parallel to the x-axis, center at (2,-2), passing through (2+3√2,0) and (2+3√10,4).
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\n" ); document.write( "This is a hyperbola with horizontal transverse axis.
\n" ); document.write( "Its standard form of equation: \"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\", (h,k)=(x,y) coordinates of center
\n" ); document.write( "For given hyperbola:
\n" ); document.write( "Given center: (2,-2)
\n" ); document.write( "Equation: \"%28x-2%29%5E2%2Fa%5E2-%28y%2B2%29%5E2%2Fb%5E2=1\"
\n" ); document.write( "using given coordinates to solve for a and b:
\n" ); document.write( "(2+3√2-2)^2/a^2-(0+2)^2/b^2=1
\n" ); document.write( "(2+3√10-2)^2/a^2-(4+2)^2/b^2=1
\n" ); document.write( "..
\n" ); document.write( "18/a^2-4/b^2=1
\n" ); document.write( "90/a^2-36/b^2=1
\n" ); document.write( "let x=1/a^2
\n" ); document.write( "let y=1/b^2
\n" ); document.write( "..
\n" ); document.write( "18x-4y=1
\n" ); document.write( "90x-36y=1
\n" ); document.write( "..
\n" ); document.write( "-162x+36y=-9
\n" ); document.write( "90x-36y=1
\n" ); document.write( "add
\n" ); document.write( "-72x=-8
\n" ); document.write( "x=8/72=1/9=1/a^2
\n" ); document.write( "a^2=9
\n" ); document.write( "..
\n" ); document.write( "4y=18x-1=2-1=1
\n" ); document.write( "y=1/4=1/b^2
\n" ); document.write( "b^2=4
\n" ); document.write( "Equation of given hyperbola:
\n" ); document.write( " \"%28x-2%29%5E2%2F9-%28y%2B2%29%5E2%2F4=1\"
\n" ); document.write( "..
\n" ); document.write( "
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