document.write( "Question 743729: Find four consecutive even integers such that twice the third integer subtracted from five times the first equals 18 more than the sum of the second and the fourth integer. \n" ); document.write( "

Algebra.Com's Answer #453034 by josgarithmetic(39630) $\"\"$ $\"About$

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Four consecutive even integers are
\n" ); document.write( "2n
\n" ); document.write( "2n+2
\n" ); document.write( "2n+4
\n" ); document.write( "2n+6\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"5%282n%29-2%2A%282n%2B4%29\"$ ------twice the third integer subtracted from five times the first\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"18%2B%282n%2B2%29%2B%282n%2B6%29\"$ --------18 more than the sum of the second and the fourth integer\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"highlight%285%282n%29-2%2A%282n%2B4%29=18%2B%282n%2B2%29%2B%282n%2B6%29%29\"$
\n" ); document.write( "Simplify and solve for n.
\n" ); document.write( "Use n found to compute each of the integers. \n" ); document.write( "

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