document.write( "Question 743705: if the median drawn on the base of a triangle is half its base, the triangle will be?
\n" ); document.write( "1.right angled
\n" ); document.write( "2.acute angled
\n" ); document.write( "3.obtuse angled
\n" ); document.write( "4.equilateral
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Algebra.Com's Answer #453022 by stanbon(75887)\"\" \"About 
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if the median drawn on the base of a triangle is half its base, the triangle will be?
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\n" ); document.write( "Sketch the triangle as it was described.
\n" ); document.write( "The median breaks the original triangle into 2 identical triangles.
\n" ); document.write( "The median equals the base in each of those triangles.
\n" ); document.write( "So each of the triangles is 45-45-90
\n" ); document.write( "Therefore the sum of the base angles of the original triangle is 45+45 = 90
\n" ); document.write( "So the vertex angle must be 90 degrees.
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\n" ); document.write( "Answer: right triangle
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "1.right angled
\n" ); document.write( "2.acute angled
\n" ); document.write( "3.obtuse angled
\n" ); document.write( "4.equilateral
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