document.write( "Question 743648: Please help me solve this equation: I've scoured the website, but I can't find one specifically like this one.
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document.write( "Distance, Rate and Time
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document.write( "John and Mary leave their house at the same time and drive in opposite directions. John drives at 60 mph and travels 35 mi farther than Mary, who drives at 40 mph. Mary's trip takes 15 min longer than John's. For what length of time does each of them drive?
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document.write( "Thanks! \n" );
document.write( "
Algebra.Com's Answer #453005 by mananth(16946)![]() ![]() You can put this solution on YOUR website! John and Mary leave their house at the same time and drive in opposite directions. John drives at 60 mph and travels 35 mi farther than Mary, who drives at 40 mph. Mary's trip takes 15 min longer than John's. For what length of time does each of them drive?\r \n" ); document.write( "\n" ); document.write( "let Mary travel x miles \n" ); document.write( "Mary speed = 40 mph \n" ); document.write( "Mary's time = x/40\r \n" ); document.write( "\n" ); document.write( "John will drive x+35 miles \n" ); document.write( "John speed = 60 mph \n" ); document.write( "john's time = (x+35)/60\r \n" ); document.write( "\n" ); document.write( "Mary's time - John's time = 1/4 hour\r \n" ); document.write( "\n" ); document.write( "x/40 - (x+35)/60 = 1/4\r \n" ); document.write( "\n" ); document.write( "LCD = 120 \n" ); document.write( "multiply eqn by 120 \n" ); document.write( "3x-2(x+35)=30\r \n" ); document.write( "\n" ); document.write( "3x-2x-70=30 \n" ); document.write( "x-70=30 \n" ); document.write( "x=100 miles=> distance driven by Mary\r \n" ); document.write( "\n" ); document.write( "distance driven by John = 135\r \n" ); document.write( "\n" ); document.write( "Time taken by Mary = 100/40 = 2.5 hours\r \n" ); document.write( "\n" ); document.write( "Time taken by John =135/60 = 2.25 hours\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |