document.write( "Question 743545: How many liters each of a acid solution and a 65% acid solution must be used to produce 50 liters of a 45% acid solution? \n" ); document.write( "
Algebra.Com's Answer #452962 by josgarithmetic(39617)\"\" \"About 
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\"How many liters each of a acid solution and a 65% acid solution...\"\r
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\n" ); document.write( "\n" ); document.write( "What is the other acid solution? What concentration? You want a result of 45% acid but you want to mix two different acid solutions; you know one of them but not the other. The other acid solution must be lower than 45%. Are you only making a dilution of the 65% acid with water, or are you really planning for mixing TWO acid solutions? This makes a difference.\r
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\n" ); document.write( "\n" ); document.write( "Assuming you have 65% and some other L% acids, and \"0%3CL%3C65\", and if you want u liters of L% and v liters of 65%, then you make equations:
\n" ); document.write( "\"%28Lu%2B65%29%2F50=45\" and \"u%2Bv=50\".
\n" ); document.write( "and you can solve the system for u and v. You still have no given value for L.
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