document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64732>Question 64732</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0028253272/algebrahomeworkh>Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A liter of cream has 9.2% butterfat. How much skim milk containing 2% butterfat should be added to the cream to obtain a mixture with 6.4% butterfat? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45295 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x= amount of skim milk to be added\r<BR>\n" );
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document.write( "We know that the amount of butterfat in the original liter (1)(.092) plus the amount of butterfat in the skim milk that was added (x)(.02) has to equal the amount of butterfat in the final mixture (1+x)(.064).  So our equation to solve is:\r<BR>\n" );
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document.write( "(1)(.092)+.02x=(1+x)(.064) simplifying, we get:<BR>\n" );
document.write( ".092+.02x=.064+.064x collecting like terms we have:<BR>\n" );
document.write( ".02x-.064x=.064-.092 or<BR>\n" );
document.write( "-.044x=-.028 and <BR>\n" );
document.write( "x=0.64 liters\r<BR>\n" );
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document.write( "ck<BR>\n" );
document.write( "(1)(.092)+(.02)(.64)=(1.64)(.064)<BR>\n" );
document.write( ".092+.013=.105<BR>\n" );
document.write( ".105=.105\r<BR>\n" );
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document.write( "Hope this helps.  Happy holidays.-----ptaylor </SPAN>\n" );
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