document.write( "Question 64775: I am studying for the TEAS Test for my nursing program and there are several questions similar to this. I know there has to be a simple formula but I can't figure it out. Thank You.\r
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document.write( "If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 min, and Jack can mix 20 drinks in 15 min, how much time will it take all 3 of them working together to mix the 20 drinks? \n" );
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Algebra.Com's Answer #45289 by stanbon(75887) ![]() You can put this solution on YOUR website! If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 min, and Jack can mix 20 drinks in 15 min, how much time will it take all 3 of them working together to mix the 20 drinks? \n" ); document.write( "--------------------------------- \n" ); document.write( "Sue DATA: \n" ); document.write( "Rate = 20 drinks/10 min \n" ); document.write( "--------- \n" ); document.write( "Jack DATA; \n" ); document.write( "Rate = 20 drinks/15 min \n" ); document.write( "--------- \n" ); document.write( "Steven DATA: \n" ); document.write( "Rate= 20 drinks/5 min \n" ); document.write( "------------------- \n" ); document.write( "Let \"x\" be the number of minutes need for the three to mix 20 drinks: \n" ); document.write( "EQUATION: \n" ); document.write( "x(Sue Rate + Jack Rate + Steven Rate) = 20 drinks \n" ); document.write( "x min(20d/10min + 20d/15min +20d/5min)= 20d \n" ); document.write( "x(2+(4/3)+4)=20 \n" ); document.write( "x(22/3)=20 \n" ); document.write( "x=60/22 \n" ); document.write( "x=30/11 \n" ); document.write( "x=2 8/11 minutes or x=2.7272... minutes \n" ); document.write( "Cheer, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |