document.write( "Question 743460: How do I verify the trigonometric identity? Cotx over 1+cotx^2 = sinxcosx\r
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document.write( "I took the numerator of the fraction (cotx) and changed it to cosx/sinx and then I took the denominator (1+cotx^2) and changed it to cscx^2 and then changed it again to 1/sinx^2. So my problem looks like (cosx/sinx)/(1/sinx^2). Is that right? I don't know where to go from there. Can you please go step by step so I can see what you did? Thank you. \n" );
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Algebra.Com's Answer #452886 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! How do I verify the trigonometric identity? Cotx over 1+cotx^2 = sinxcosx\r \n" ); document.write( "\n" ); document.write( "I took the numerator of the fraction (cotx) and changed it to cosx/sinx and then I took the denominator (1+cotx^2) and changed it to cscx^2 and then changed it again to 1/sinx^2. So my problem looks like (cosx/sinx)/(1/sinx^2). Is that right? I don't know where to go from there. \n" ); document.write( "===================== \n" ); document.write( "cot/(1+cotx^2) = sinxcosx \n" ); document.write( "cot/csc^2 = sin*cos \n" ); document.write( "--- \n" ); document.write( "(cos/sin)/(1/sin^2) = sin*cos \n" ); document.write( "cos*sin^2/sin = sin*cos \n" ); document.write( "cos*sin = cos*sin \n" ); document.write( " |